SOLUTION: "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
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Question 212410This question is from textbook Intermediate Algebra
: "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
I respectfully request if you can show all work. Thank you very much. This question is from textbook Intermediate Algebra
You can put this solution on YOUR website! "The distance that a freely falling body falls varies directly as the square of the time it falls. If a body falls 400 feet in 5 seconds, how far does it fall in 3 seconds?"
s = kt^2 s = distance, k = a constant
400 = k*5^2 = 25k
k = 400/25 = 16
--> s = 16t^2
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For 3 seconds:
s = 16*9
s = 144 feet
