SOLUTION: I'm having the same problem again. <a href="http://s222.photobucket.com/albums/dd239/terragilles/?action=view&current=img28.gif" target="_blank"><img src="http://i222.photo

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm having the same problem again. <a href="http://s222.photobucket.com/albums/dd239/terragilles/?action=view&current=img28.gif" target="_blank"><img src="http://i222.photo      Log On


   

Question 212303: I'm having the same problem again.


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I'm not having any luck getting my graphing calculator to work with log function. Is there any easier way to work these?
Found 2 solutions by Alan3354, rapaljer:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!

I'm not having any luck getting my graphing calculator to work with log function. Is there any easier way to work these?
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y+=+log%285%2C-x%29
To have a logarithm, a number has to be greater than zero.
In this case, -x has to be greater than zero, so x has to be less than zero.
Graphing calculators may not be equipped to handle that.
To graph it, dl the FREE software at
http://www.padowan.dk.com

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Are you working with y=+%28log+%2810%2C-x%29%29%2Flog+%2810%2C5%29+? This should work, with values of y being generated for NEGATIVE values of x.

Let me see how the algebra.com graph works:
graph%28300%2C300%2C+-10%2C10%2C-10%2C10%2C+log%2810%2C-x%29%2F%28log%2810%2C5%29%29+%29+

R^2

Dr. Robert J. Rapalje, Retired
Seminole Community College