Question 212102: Find the x intercepts for the parabola y = x2 – 6x + 5.
Find the vertex of the parabola y = - 2x2 + 8x + 4
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! Find the x intercepts for the parabola y = x2 – 6x + 5.
Step 1. For this problem y=0 since we want x-intercepts.
Step 2. Use quadratic formula:
where a=1, b=-6 and c= 5
Step 3. The following steps shows how to solve the above equation in Step 2 where you will find x=1 and x=5. Note the parabola intercepts x-axis when y=6 at these points.
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=16 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 5, 1.
Here's your graph:
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Problem: Find the vertex of the parabola y = - 2x2 + 8x + 4
Step 1. Graph is shown below and the vertex is at (2,12)
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=96 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: -0.449489742783178, 4.44948974278318.
Here's your graph:
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