SOLUTION: a picture is 4 inches longer then wide. it a 1 inch frame is put on and the area is increased by 48 square inches. whats the dimensions of the picture
Algebra ->
Rectangles
-> SOLUTION: a picture is 4 inches longer then wide. it a 1 inch frame is put on and the area is increased by 48 square inches. whats the dimensions of the picture
Log On
Question 211987: a picture is 4 inches longer then wide. it a 1 inch frame is put on and the area is increased by 48 square inches. whats the dimensions of the picture Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! "a picture is 4 inches longer than it's wide."
:
Let x = the width of the picture
then
(x+4) = the length
:
"if a 1 inch frame is put on, the area is increased by 48 square inches."
(x+4)+ 2 =
(x+6) = overall length
and
(x+2) = overall width
:
"what's the dimensions of the picture"
:
Overall area - picture area = 48 sq/in
:
(x+6)(x+2) - x(x+4) = 48
FOIL
x^2 + 2x + 6x + 12 - (x^2 + 4x) = 48
x^2 + 8x + 12 - x^2 - 4x = 48
x^2 - x^2 + 8x - 4x = 48 - 12
4x = 36
x =
x = 9 in is width of the picture
and
9 + 4 = 13 in is the length
;
:
Check solution:
15*11 - 13*9 =
165 - 117 = 48
