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| Question 211833:  The product of two consecutive odd integers is 1 less than four times their sum.
 Find the two integers.
 Answer by RAY100(1637)
      (Show Source): 
You can put this solution on YOUR website! Let x, x+2 be  consecutive integers .
 (x)(x+2) = 4(x+x+2) -1 = 4(2x+2)-1
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 x^2 +2x = 8x +8 -1
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 x^2 -6x -7 =0
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 (x-7)(x+1) = 0
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 x+7,,,,-1
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 consecutive integers,,7,9,,,,,-1,1
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 check,,,(7,9),,,7*9 = 4(7+9) -1 = 63,,,,ok
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 (-1,1),,,,,-1*1 = 4(-1+1) -1 = -1,,,,ok
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