SOLUTION: determine the linear velocity of a point rotating at 25 revolutions per minute at a distance of 2 feet from the center of the rotating object. a)2.6 ft/sec b)314.2 ft/sec

Algebra ->  Trigonometry-basics -> SOLUTION: determine the linear velocity of a point rotating at 25 revolutions per minute at a distance of 2 feet from the center of the rotating object. a)2.6 ft/sec b)314.2 ft/sec       Log On


   

Question 211813: determine the linear velocity of a point rotating at 25 revolutions per minute at a distance of 2 feet from the center of the rotating object.
a)2.6 ft/sec
b)314.2 ft/sec
c)5.2 ft/sec
d)78.5 ft/sec
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
A point on the circumference of a circle of radius = 2ft. rotating at 25 rpm would have a linear velocity of:
25%2A2%28pi%29%28r%29+=+50%2A%28pi%29%2A%28r%29 Substitute r+=+2 and pi+=+3.142, then the linear velocity would be:
v%5Bl%5D+=+25%2A2%283.142%29%2A2
V%5Bl%5D+=+314.2ft.per sec.