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Question 211714: 3x-5/x^2-5>0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 3x-5/x^2-5>0
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Find values that are not solutions to the inequality.
3x-5 cannot be zero
x cannot be 5/3
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x^2-5 cannot be zero
x cannot be sqrt(5)
x cannot be -sqrt(5)
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Plot those three points on a number line ; check a value in each of the
intervals to see where solution for the inequality are.
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If x = -10 you get -/+ >0 ; false
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If x = 0 you get -/- > 0 ; true so solutions in (-sqrt(5),5/3)
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If x = 2 you get +/- >0 ; false
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If x = 10 you get +/+ >0 ; true so solutions in (sqrt(5, + inf)
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Cheers,
Stan H.
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