SOLUTION: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=

Algebra ->  Linear-equations -> SOLUTION: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=      Log On


   

Question 211562: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=2L+2W.
a) Set up an equation for the perimeter involving only L, the length of the rectangle.
Answer:
b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
Answer: Length ______, Width ______
Show your work here:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
W=L-5
2L+2W=50
2L+2(L-5)=50
2L+2L-10=50
4L=40
L=40/4
L=10 ANS. FOR THE LENGTH.
W=10-5
W=5 ANS. FOR THE WIDTH.
PROOF:
2*10+2*5=50
40+10=50
50=50
Answer: Length 10 IN., Width 5 IN.