SOLUTION: Express as an equivalent expression, using the individual logarithms of w,x,y,and z. logb w^2x/y^3z

Algebra ->  Expressions-with-variables -> SOLUTION: Express as an equivalent expression, using the individual logarithms of w,x,y,and z. logb w^2x/y^3z      Log On


   



Question 211501This question is from textbook Elementary and Intermediate Algebra
: Express as an equivalent expression, using the individual logarithms of w,x,y,and z.
logb w^2x/y^3z
This question is from textbook Elementary and Intermediate Algebra

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
logb w^2x/y^3z
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I believe this is meant to be:
log%28b%2Cw%5E2%2Ax%2Fy%5E3%2Az%29
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That is the equation I am working with.
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The logarithmic properties we will be using are:
log(a*b) = log(a) + log(b)
log(a/b) = log(a) - log(b)
log(a^c) = c*log(a)
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your equation is broken up into parts that can be converted to log form easy.
I made it look like this:
(w^2) * x * z / (y^3)
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We will take the log to the base b of this expression as is.
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we get:
log%28b%2C%28%28w%5E2%29%2Ax%2Az+%2F+%28y%5E3%29%29%29
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First we'll separate out the individual entities I created.
The equation becomes:
log%28b%2C%28%28w%5E2%29%2Ax%2Az+%2F+%28y%5E3%29%29%29 =
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Next we'll take care of the exponent entries.
log%28b%2C%28%28w%5E2%29%2Ax%2Az+%2F+%28y%5E3%29%29%29 = becomes:
log%28b%2C%28%28w%5E2%29%2Ax%2Az+%2F+%28y%5E3%29%29%29 =
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To prove your answer is correct, you give some values to your variables and you solve using the original equation and you solve using the final equation.
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If you get the same answer, then that's a good indication that you did it right.
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I verified they are the same.
I used:
base = 10 (calculator can handle that)
w = 5
x = 3
y = 4
z = 2
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make sure you keep the exponents and roots intact (roots are just another form of exponents) until after you have separated all the multiplies and divides.
that's why I made them separate entities by enclosing them in parentheses.
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