SOLUTION: how do you solve... logx 16 = -4
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Question 211484
:
how do you solve...
logx 16 = -4
Answer by
nerdybill(7384)
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Applying "log rules":
logx 16 = -4
16 = x^(-4)
16 = 1/x^4
16x^4 = 1
x^4 = 1/16
x = 1/2