Question 211463: Factoring
4x^2 + 19xy + 12y^2
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! 4x^2 +19xy +12y^2
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sign of 3rd term is (+) therefore both factors have same sign
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sign of second term is (+) ,,,therefore both factors are (+)
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factors of 1st term are,, 1*4,,2*2
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Factors of 3rd term are, 1*12,,2*6,,3*4,,
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Seeking a combination whose factors add to 19
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Try,,,4*4 + 1*3 = 16+3 = 19
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(4x +3y)(1x +4y)
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