SOLUTION: Can you please help me with this problem? Find the dimensiona of a rectangle whose area is 180cm^2 and whose perimeter is 54 cm. Please show me all the steps and reply as soon as p

Algebra ->  Rectangles -> SOLUTION: Can you please help me with this problem? Find the dimensiona of a rectangle whose area is 180cm^2 and whose perimeter is 54 cm. Please show me all the steps and reply as soon as p      Log On


   

Question 211405This question is from textbook College Algebra
: Can you please help me with this problem? Find the dimensiona of a rectangle whose area is 180cm^2 and whose perimeter is 54 cm. Please show me all the steps and reply as soon as possible this is due tues. before 10 am.
Thank you This question is from textbook College Algebra

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Let w= width
L = length

Perimeter: 2W + 2L = 54

Divide this by 2: w+ L = 27
Solve for w: W = 27 - L

Now, Area = L*W
L*W = 180

Substitute W = 27-L to get an equation in one variable:
L * (27-L) = 180
27L - L^2 = 180

This is a quadratic equation, so set it equal to zero. I recommend you move everything to the right side to avoid the negative L^2 coefficient:
0 = L^2 - 27 - 180

Now,since this seems to be a take home problem that is DUE in Tuesday morning, YOU solve the equation!!

R^2