SOLUTION: Please me find the equation of the line going through the point (-2,-3) and perpendicular to -2X+3Y=8

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Question 211337: Please me find the equation of the line going through the point (-2,-3) and perpendicular to -2X+3Y=8
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope of the given line:
-2x%2B3y+=+8 Add 2x to both sides.
3y+=+2x%2B8 Divide both sides by 2.
y+=+%282%2F3%29x%2B8%2F3 Compare this with the slope-intercept form:
y+=+mx%2Bb
The slope is:m+=+2%2F3 If a line is perpendicular to this, its slope will be the negative reciprocal or m+=+-3%2F2 so we can start with:
y+=+%28-3%2F2%29x%2Bb Now we find b by substituting the x- and y-coordinates from the given point:
-3+=+%28-3%2F2%29%28-2%29%2Bb
-3+=+3%2Bb
b+=+-6
The equation is:
y+=+%28-3%2F2%29x-6