SOLUTION: Three years ago, Jeff was twice as old as Mike is now. In nine years, Jeff will be four years older than Mike is now. What are their current ages?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Three years ago, Jeff was twice as old as Mike is now. In nine years, Jeff will be four years older than Mike is now. What are their current ages?       Log On


   



Question 211329: Three years ago, Jeff was twice as old as Mike is now. In nine years, Jeff will be four years older than Mike is now. What are their current ages?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Three years ago, Jeff was twice as old as Mike is now. In nine years, Jeff will be four years older than Mike is now. What are their current ages?
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Let jeff's age now be "j".
Let mike's age now be "m".
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Equations:
j-3 = 2m
j+9= m+4
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Rearrange:
j = 2m+3
Substitute:
2m+3 + 9 = m+4
m = -8 (this is an unrealistic answer; please check your problem statement)
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Cheers,
Stan H.