You can put this solution on YOUR website! please answer this question : (f+g)x
given that f(x)=2/x and g(x)=X2+3x+2
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(f+g)(x) = f(x) + g(x) = (2/x) + x^2+3x+2
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Cheers,
Stan H.
You can put this solution on YOUR website! about the most straight forward tutorial i have found on this subject is at this web address:
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http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut30b_operations.htm
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(f+g)(x) is equal to f(x) + g(x)
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your problem is:
find (f+g)(x) given that f(x)=2/x and g(x)=X2+3x+2
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you have f(x) = 2/x
you have g(x) = x^2 + 3x + 2
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(f+g)(x) = f(x) + g(x) = 2/x + x^2 + 3x + 2
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this becomes:
x^2 + 3x + 2 + 2/x
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I'm not exactly sure how or whether this can be reduced further.
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you're supposed to add these functions together and combine like terms.
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multiplying each of the components by x/x except for the term 2/x would make all components /x which allows them to be combined in the numerator of the function.
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you would get:
x^3/x + 3x^2/x + 2x/x + 2/x which would become:
(x^3 + 3x^2 + 2x + 2)/x
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the two forms of the equation are equivalent, i.e.
x^2 + 3x + 2 + 2/x is equivalent to (x^3 + 3x^2 + 2x + 2)/x
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since neither form allowed any combining of like terms more then the other, I would think that either form would be acceptable.
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if they were just trying to teach you that (f+g)(x) equals f(x) + g(x), then either form should give you a proper answer.
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