SOLUTION: Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the this i

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the this i      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 211106This question is from textbook ETS GRE
: Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the this investment is $256, how much did Pat invest at 10 percent and how much at 8 percent? This question is from textbook ETS GRE

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.10x+.08(3,000-x)=256
.10x+240-.08x=256
.02x=256-240
.02x=16
x=16/.02
x=800 amount invested @ 10%
3,000-800=2,200 invested @ 8%
Proof:
.10*800+.08*2,200=256
80+176=256
256=256