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| Question 211106This question is from textbook ETS GRE
 :  Pat invested a total of $3,000. Part of the money yields 10 percent interest per year, and the rest yields 8 percent interest per year If the total yearly interest from the  this investment is $256, how much did Pat invest at 10 percent and how much at 8 percent? 
This question is from textbook ETS GRE
 
 Answer by checkley77(12844)
      (Show Source): 
You can put this solution on YOUR website! .10x+.08(3,000-x)=256 .10x+240-.08x=256
 .02x=256-240
 .02x=16
 x=16/.02
 x=800 amount invested @ 10%
 3,000-800=2,200 invested @ 8%
 Proof:
 .10*800+.08*2,200=256
 80+176=256
 256=256
 
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