SOLUTION: Can anyone help me with the below word problem. Is it standard deviation? The weights of the full-grown adult male South American tapir are normally distributed with a mean of

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Question 211051: Can anyone help me with the below word problem. Is it standard deviation?
The weights of the full-grown adult male South American tapir are normally distributed with a mean of 525 pounds and a standard deviation of 35 pounds. What is the probability that
a) A randomly selected full-grown adult male tapir weighs at least 550 pounds?
b) A randomly selected full-grown adult male tapir weighs less than 450 pounds?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The weights of the full-grown adult male South American tapir are normally distributed with a mean of 525 pounds and a standard deviation of 35 pounds. What is the probability that
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Comment: You either have to use a z-table or a calculator to get these
answers. I use a TI-84
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a) A randomly selected full-grown adult male tapir weighs at least 550 pounds?
Ans: 1 - normalcdf(0,550,525,35) = 0.2375
OR
z(550)=(550-525)/35 = 0.714
P(x>=550) = P(z>=0.714) = 0.2376
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b) A randomly selected full-grown adult male tapir weighs less than 450 pounds?
Ans: normalcdf(0,450,525,35) = 0.0161
z(450)= (450-525)/35 = -2.143
P(x<45) = P(z<-2.143) = 0.0161...
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Cheers,
Stan H.