SOLUTION: sorry i got it off a worksheet:
f(x)=x^2 + 2x + 5
i have to write each quadratic function in vertex form, give coordinates of the vertex, and the equation of the axis of symmet
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Rational-functions
-> SOLUTION: sorry i got it off a worksheet:
f(x)=x^2 + 2x + 5
i have to write each quadratic function in vertex form, give coordinates of the vertex, and the equation of the axis of symmet
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Question 210900: sorry i got it off a worksheet:
f(x)=x^2 + 2x + 5
i have to write each quadratic function in vertex form, give coordinates of the vertex, and the equation of the axis of symmetry. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! f(x)=x^2 + 2x + 5
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The axis of symmetry is the line x = -b/2a
x = -2/2 = -1
x = -1 (equation of axis of symmetry)
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f(x)=x^2 + 2x + 5
f(x)=(x^2 + 2x) + 5
f(x)=(x^2 + 2x + __ ) + 5
f(x)=(x^2 + 2x + 1 ) + 5 - 1
f(x)=(x+1)^2 + 4
f(x)=(x-(-1))^2 + 4 (vertex form)
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vertex is at (-1,4)
