SOLUTION: x^2+3x-40=0 How would you solve this equation?
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Question 21074
:
x^2+3x-40=0
How would you solve this equation?
Answer by
kapilsinghi(68)
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x^2+3x-40=0
x^2+8x-5x-40=0
x(x+8)-5(x+8)=0
(x-5)(x+8)=0
x=5 or x=-8
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