SOLUTION: -3x≤3x+7≤½

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Question 210669: -3x≤3x+7≤½
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
-3x%3C=3x%2B7%3C=1%2F2

Note we can get two inequalities out of this:

highlight%28-3x%3C=3x%2B7%29%3C=1%2F2  AND -3x%3C=highlight%283x%2B7%3C=1%2F2%29

So we write:

-3x%3C=3x%2B7 AND 3x%2B7%3C=1%2F2

Add -3x to both sides of the first inequality.
Multiply the second inequality through by 2 to
clear of fractions:

-6x%3C=7 AND 6x%2B14%3C=1

Divide the first inequality through by -6
which reverses the sign of inequality:
Add -14 to both sides of the second

x%3E=7%2F%28-6%29 AND 6x%3C=-13

Simplify the first and divide the second through
by 6 (which BTW does not reverse the sign of
inequality):

x%3E=-7%2F6 AND x%3C=-13%2F6

It's easier to see if we change the
improper fractions to mixed fractions

x%3E=-1%261%2F6 AND x%3C=-2%261%2F6

As you can see this is a contradiction because
the same value of x cannot be to the right of
-1%261%2F6  AND also to the left of -2%261%2F6.

Thus the solution set is the empty, or null, set, Ø

Edwin