Question 210360: The average temperature for a five-day business week was 23 degrees. The temperatures for three of the days were 21 degrees, 30 degrees , and 22degrees respectively. Of the two remaining days, the warmer of the two is 6 degrees more than the cooler of the two. Determine the cooler of the two remaining temperatures.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The average temperature for a five-day business week was 23 degrees. The temperatures for three of the days were 21 degrees, 30 degrees , and 22degrees respectively. Of the two remaining days, the warmer of the two is 6 degrees more than the cooler of the two. Determine the cooler of the two remaining temperatures.
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Let the cooler temperature be "x".
Then the warmer is "x+6"
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Equation:
(21+21+21+x+(x+6))/5 = 23
63 + x + 6 = 115
x = 115-69
x = 46 degrees (the cooler day)
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Cheers,
Stan H.
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