SOLUTION: Simon drew a rectangle whose width is 6 inches less than its length. The perimeter of the rectangle is 6 feet. What are the dimensions of the rectangle Simon drew?I need length and

Algebra ->  Rectangles -> SOLUTION: Simon drew a rectangle whose width is 6 inches less than its length. The perimeter of the rectangle is 6 feet. What are the dimensions of the rectangle Simon drew?I need length and      Log On


   

Question 210359: Simon drew a rectangle whose width is 6 inches less than its length. The perimeter of the rectangle is 6 feet. What are the dimensions of the rectangle Simon drew?I need length and width in inches! Thanks a Bunch!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6 feet = 72 inches
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Simon drew a rectangle whose width is 6 inches less than its length. The perimeter of the rectangle is 6 feet. What are the dimensions of the rectangle Simon drew?I need length and width in inches
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Width = L-6
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Equation:
Perimeter = 2(L + W)
72 = 2(L + L-6)
36 = 2L-6
2L = 42
L = 21 inches (length)
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W = L-6 = 15 inches (width)
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Cheers,
Stan H.