SOLUTION: I was working on my Algebra and it came up with a Geometry Problem. Sorry Only thing I know of is that I must do x=3 . After that im lost.
Heres the Problem.
Find the length a
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-> SOLUTION: I was working on my Algebra and it came up with a Geometry Problem. Sorry Only thing I know of is that I must do x=3 . After that im lost.
Heres the Problem.
Find the length a
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Question 210150: I was working on my Algebra and it came up with a Geometry Problem. Sorry Only thing I know of is that I must do x=3 . After that im lost.
Heres the Problem.
Find the length and width of a rectangle which has a perimeter of 24. And the Length is 3 inches greater then the width. Found 2 solutions by Alan3354, jim_thompson5910:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the length and width of a rectangle which has a perimeter of 24. And the Length is 3 inches greater then the width.
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Perimeter = 2L + 2W
L = W + 3 (length is 3 more than width)
Sub for L in 1st equation
P = 2(W + 3) + 2W
24 = 2W + 6 + 2W
24 = 4W + 6
4W = 18
W = 4.5 inches
L = 7.5 inches
You can put this solution on YOUR website! The perimeter P of any rectangle with length L and width W is . Since the rectangle has "a perimeter of 24", this means . Plug this in to get . This is our first equation.
Also, since "the Length is 3 inches greater then the width", this means that we take the unknown width W and add 3 inches to it to get the length L. Algebraically, we get:
Start with the first equation.
Plug in
Distribute.
Combine like terms.
Subtract from both sides.
Combine like terms.
Divide both sides by to isolate .
Reduce.
Rearrange the equation.
Divide
So the width is 4.5 inches.
Since the length is "3 inches greater then the width", just add 3 to the width to get the length like so:
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Answer:
So the length and width are 7.5 inches and 4.5 inches respectively.
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