Question 210120: find the inverse of f(x)=2 sqrt(x+3)
a) f^-1(x)=(x-3/2)^2
b)f^-1(x)= (x+3/2)^2
c)f^-1(x)= 1/2 sqrt(x-3)
d)f^-1(x)= 1/2 sqrt(x+3) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the inverse of f(x)=2 sqrt(x+3)
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Interchange x and y then solve for "y":
x = 2sqrt(y+3)
sqrt(y+3) = x/2
y+3 = (x^2/4)
y = (x^2/4)-3
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That is the inverse but it is not listed as one of your options.
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Cheers,
Stan H.
a) f^-1(x)=(x-3/2)^2
b)f^-1(x)= (x+3/2)^2
c)f^-1(x)= 1/2 sqrt(x-3)
d)f^-1(x)= 1/2 sqrt(x+3)
(