SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60mph, Train B traveling at 64mph. Train A passes by the station at 4:15am and train B pa
Question 210049: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60mph, Train B traveling at 64mph. Train A passes by the station at 4:15am and train B passes the same station at 4:45am, at what time will the train B catch up to train A? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parallel tracks. Train A is traveling 60mph, Train B traveling at 64mph. Train A passes by the station at 4:15am and train B passes the same station at 4:45am, at what time will the train B catch up to train A?
:
from the given information, we know that train B is 30 min, (.5 hrs) behind
train A, when train A passes the station
:
The distance between the trains at this time: .5 * 64 = 32 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 32 mi
64t = 60t + 32
64t - 60t = 32
4t = 32
t =
t = 8 hrs
:
4:15 AM + 8:00 = 12:15 pm, B catches A
