what is the solution of, a two digit number is four times the sum of its digits and thrice the product of its digits. find the number.
t = tens digit
u = ones digit
the two digit number = 10t+u
t+u = sum of the digits
tu = product of the digits
>>...A two digit number is four times the sum of its digits...<<
So
Distribute on the right
Simplify:
Divide both sides by 3
>>...a two digit number is...thrice the product of its digits...<<
So we have this system of equations:
Substitute
for
in the 2nd equation
Combine terms on the left
Divide through by 6
Factor out
Set each factor = 0
The ten's digit cannot be 0 for a 2-digit number.
So
Substitute that in
So since
and
,
The number is
.
Checking:
The sum of the digits is 2+4 or 6
So 24 is 4 times the sum of its digits,
because 24 is 4 times 6.
The product of the digits is 2×4 = 8
So 24 is thrice the product of its digits,
because 24 is 3 times 8.
It checks.
Edwin