SOLUTION: Translate the problem situation to a system of equations. Do not attempt to solve.
The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the len
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The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the len
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Question 209762: Translate the problem situation to a system of equations. Do not attempt to solve.
The perimeter of a rectangular building is 234 feet. The width is 25 feet shorter than the length. What are the dimensions? (Let W represent the width and L represent the length.)
A) W = L - 25, 2L + 2W = 234
B) W = L - 25, L + W = 234
C) L = W - 25, 2L + W = 234
D) W = L + 25, 2L + 2W = 234 Answer by 314(4) (Show Source):
You can put this solution on YOUR website! Perimeter = 2( W+L); W=L-25
234=2(L-25+L) we divide with 2 (both sides of the equation)
117=2L+25
2L=117-25
2L=92 we divide with 2
L=46 feet
W=L-25=46-25=21 feet
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