SOLUTION: solve: 1+square root(x+7)=square root(3x-2)

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Question 209756This question is from textbook
: solve:
1+square root(x+7)=square root(3x-2)
This question is from textbook

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
1+square root(x+7)=square root(3x-2)
1+%2B+sqrt%28x%2B7%29 = sqrt%283x-2%29
Square both sides, (FOIL the left):
1+%2B+2sqrt%28x%2B7%29+%2B+%28x%2B7%29 = 3x+-+2
:
x+%2B+8+%2B+2sqrt%28x%2B7%29 = 3x+-+2
:
2sqrt%28x%2B7%29 = 3x+-x+-+2+-+8
:
2sqrt%28x%2B7%29 = 2x+-+10
Square both sides again, (FOIL the right side)
4(x + 7) = 4x^2 - 20x - 20x + 100
:
4x + 28 = 4x^2 - 40x + 100
:
0 = 4x^2 - 40x - 4x + 100 - 28
a quadratic equation
4x^2 - 44x + 72 = 0
Simplify divide by 4
x^2 - 11x + 18 = 0
Factor
(x-9)(x-2) = 0
Two solutions
x = 9
x = 2
:
It's important that you test both solutions in the original equation, one may not be valid.
I'll let you do that