SOLUTION: i worked this problem like this: (e^2x) - (3e^x) + 2 = 0 (e^2x) - (3e^x) = -2 e^(2x\x^3) = e^(-2) (2\x^2)= e^(-2) 2= e^(-2x^2) (2\e^-2) = x^2 sqrt(14.778)= sqrt(x^2) x=3.84

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: i worked this problem like this: (e^2x) - (3e^x) + 2 = 0 (e^2x) - (3e^x) = -2 e^(2x\x^3) = e^(-2) (2\x^2)= e^(-2) 2= e^(-2x^2) (2\e^-2) = x^2 sqrt(14.778)= sqrt(x^2) x=3.84      Log On


   

Question 209750: i worked this problem like this:
(e^2x) - (3e^x) + 2 = 0
(e^2x) - (3e^x) = -2
e^(2x\x^3) = e^(-2)
(2\x^2)= e^(-2)
2= e^(-2x^2)
(2\e^-2) = x^2
sqrt(14.778)= sqrt(x^2)
x=3.844
i tried my answer. but it doesnt work out.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(e^2x) - (3e^x) + 2 = 0
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It may not look like but this is a quadratic equation.
(e^x)^2 - 3e^x + 2 = 0
Factor to get:
(e^x-2)(e^x-1) = 0
e^x = 2 or e^x = 1
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Take the natural log of each to solve for "x":
x = ln(2) or x = ln(1)
x = 0.6931.. or x = 0
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Cheers,
Stan H.
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