SOLUTION: A rectangle has a perimeter of 14 feet. If the twice its length is equal to one less than four times its width, find the rectangle's length and width.

Click here to see ALL problems on Rectangles

Question 209740: A rectangle has a perimeter of 14 feet. If the twice its length is equal to one less than four times its width, find the rectangle's length and width.
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website!
A rectangle has a perimeter of 14 feet. If the twice its length is equal to one less than four times its width, find the rectangle's length and width.

Step 1. Let L be the length of rectangle and let w be the width

Step 2. Translate the following into an equation: If the twice its length is equal to one less than four times its width, find the rectangle's length and width.

is twice the length

is one less than four time its width. So now

Divide by 2 to both sides of equation

Step 3. Let P = 14 ft be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,

But

Step 4. Add 1 to both sides of equation to get 62 by itself

Step 5. Divide 5 to both sides of equation

Step 5. w = 5/2 is the width of the rectangle and length is 9/2 since

Check P=6w-1= 6*(5/2)-1= 14 So w = 5/2 ft and L=9/2 is the solution.

Hope the above steps were helpful. Good luck in your homework and studies!

Respectfully
Dr J

Hope you understood and followed the steps. Good luck in your studies. Dr J

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trig Vids please visit http://www.FreedomUniversity.TV/courses/Trigonometry