SOLUTION: I need major help on logarithms.
if i have:
ln(x-2)+ ln(2x-3)= 2lnx
i know that im supposed to
have
ln((x-2)(2x-3))=lnx^2
which would eliminate the ln
but what do i
Question 209708: I need major help on logarithms.
if i have:
ln(x-2)+ ln(2x-3)= 2lnx
i know that im supposed to
have
ln((x-2)(2x-3))=lnx^2
which would eliminate the ln
but what do i do afterwards? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! ln(x-2)+ ln(2x-3)= 2lnx
ln((x-2)(2x-3))=lnx^2
(x-2)(2x-3) = x^2
2x^2 - 7x + 6 = x^2
x^2 - 7x + 6 = 0
(x-1)*(x-6) = 0
x = 1 This won't work as ln(1-2) is not allowed.
x = 6
