Question 209552: Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex.
(A) y = -2(x+2)(x-2);(0,-2)
(B) y = -2(x+2)(x-2);(0,0)
(C) y = -2(x+2)(x+2);(-4,-8)
(D) y = -2(x-2)(x-2);(4,-8)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Rewrite the equation y = (x+2)(4-2x) in intercept form. Then state the coordinates of the vertex.
--------------------
y = (x+2)(-2(x-2))
y = -2(x^2-4)
y = -2x^2 + 8
--
Vertex occurs at x = -b/2a = 0/-4 = 0
f(0) = 8
---
So, vertex at (0,8)
------------------------------
------
Cheers,
Stan H.
Reply to stanbon@comcast.net
========================================
(A) y = -2(x+2)(x-2);(0,-2)
(B) y = -2(x+2)(x-2);(0,0)
(C) y = -2(x+2)(x+2);(-4,-8)
(D) y = -2(x-2)(x-2);(4,-8)
|
|
|
