SOLUTION: three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers?
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Question 209550: three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers? Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! three consecutive even integers are such that the sum of the smallest and 3 times the second is 38 more than twice the third. what are the integers?
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1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
2x-2 +3(2x)= 2x+2+38
2x-2 + 6x = 2x +40
6x = 42
x = 7
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1st: 14-2 = 12
2nd: 14
3rd: 14+2 = 16
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Cheers,
Stan H.
Reply to stanbon@comcast.net
You can put this solution on YOUR website!
Let the smallest integer be I
Then the 2nd and 3rd are (I + 2) and (I + 4)
Since the sum of the smallest and 3 times the second is 38 more than twice the 3rd, then we get:
(