Question 209422: I am having a problem with solving the word equations. Im not sure of how to write them out.
This is one I have to solve:
Find three consecutive even integers such that eight times the sum of the first two integers is eight more than twelve times the third integer.
This is what I wrote out but I don't believe it is right:
8(x+x)=8 + 12(x+3)
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Good start
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Let consecutive EVEN integers be,,,x,,,,,x+2,,,,x+4
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then equation becomes,,,,8{(x) +(x+2)} = 8+12(x+4)
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simplify
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8{2x+2} = 8 +12x + 48
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16x +16 =8 +12x +48
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4x = 40
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x=10,,,integers are,,,10,,,12,,,14
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check,,,8(10+12) = 8 + 12(14)
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8(22) =8 + 12(14)
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176 = 8+168 = 176,,,,ok
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NOTE, the relation x,,x+2,,x+4,,etc,,,,works for consecutive EVEN or ODD integers
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