Question 209408: how is this problem factored.
3xy^2+11xy-20x
Found 2 solutions by RAY100, stanbon:
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! 3xy^2 +11xy -20x,,,,if we factor common term (x)
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x(3y^2 +11y-20)
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looking at second factor
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last term is (-), therefore factors have different signs, and second term is difference of factors
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Middle term is (+), therefore, largest factor is (+)
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factor of 1st term is,,, 1*3
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factors of last term are,,,1*20,,2*10,,,4*5
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x(3y-4)(y+5),,,,,answer
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check by multiplying factors
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(3xy -4x)(y+5)
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3xy^2 +15xy -4xy -20x
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3xy^2 +11xy -20x,,,,,,,ok
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Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! how is this problem factored.
3xy^2+11xy-20x
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Think of two numbers whose product is 3*-120 = -60
and whose sum or difference is 11
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The numbers are 15 and 4
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Rewrite the problem:
x(3y^2 + 11y - 20)
x(3y^2 + 15y - 4y - 20)
x(3y(y+5)-4(y+5))
x(y+5)(3y-4)
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Cheers,
Stan H.
Reply to stanbon@comcast.net
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