SOLUTION: A photograph measures 8 in. by 10 in. Earl put it in a frame that is 2 in. wide. Find the area of the frame and its outside perimeter.
Unknown: length of frame
Known: width o
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Unknown: length of frame
Known: width o
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Question 209260: A photograph measures 8 in. by 10 in. Earl put it in a frame that is 2 in. wide. Find the area of the frame and its outside perimeter.
Unknown: length of frame
Known: width of frame
photo is 8 in. x 10 in.
A=lw
a=l x 2 in.
You can put this solution on YOUR website! I assume you want the area of the frame less the area of the picture?
(8+2)(10+2)-(8*10)=40q in of frame
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P=2w+2l
P=2(12)+2(10)
P=44 in outside perimeter
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