SOLUTION: if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a = a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3

Algebra ->  Functions -> SOLUTION: if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a = a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3       Log On


   



Question 209241: if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a =
a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
if f(x) = x^2 + 3x +2 then [f(x+a)- f(x)]/a =
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f(x+a) = (x+a)^2 + 3(x+a) +2
f(x+a) = x^2 +2ax + a^2 + 3x + 3a + 2
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Subtract f(x) from f(x+a) to get:
2ax + a^2 + 3a
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Divide by "a" to get the final answer:
2x + 3 + a
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Cheers,
Stan H.
Reply to stanbon@comcast.net
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a) 2x+a+3 b) (x+ a)^2 - x^2 c) a^2 + 2ax + 3a d) 2x + a e) 2x+3