SOLUTION: A rectangular dog pen is twice as long as it is wide. The perimeter of the pen is 36ft. Find the length and width of the pen.
W=width
w x 2=length
P=2l + 2w
p=36= 2 (w x 2)+
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-> SOLUTION: A rectangular dog pen is twice as long as it is wide. The perimeter of the pen is 36ft. Find the length and width of the pen.
W=width
w x 2=length
P=2l + 2w
p=36= 2 (w x 2)+
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Question 209221This question is from textbook Prealgebra & Introductory Algebra
: A rectangular dog pen is twice as long as it is wide. The perimeter of the pen is 36ft. Find the length and width of the pen.
W=width
w x 2=length
P=2l + 2w
p=36= 2 (w x 2)+ 2 x w
36= 2w x 4 + 2w
36= 4w x 4 This question is from textbook Prealgebra & Introductory Algebra
"36= 2w x 4 + 2w" ___ this is not ___ the parentheses caused a problem??
___ distributive law not needed for multiplication __ just remove parentheses and multiply
