Question 209214This question is from textbook Pre-Algebra
: Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have? This question is from textbook Pre-Algebra
You can put this solution on YOUR website! Jess has 3 more nickels than dimes for a total of $1.50. How many of each coin did he have?
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Quantity Eq: n = d + 3
Value Eq: 5n + 10d = 150 cents
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Substitute to solve for "d":
5(d+3)+10d = 150
15d + 15 = 150
15d = 135
d = 9 (# of dimes)
n = d+3 = 9+3 = 12 (# of nickels)
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Cheers,
Stan H.
Reply to stanbon@comcast.net
You can put this solution on YOUR website! Suppose he had all nickels. That would be nickels
Suppose I change of those nickels
for dimes. I have or dimes
and or nickels
Now I'll change nickels into dimes:
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18 nickels
6 dimes
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16 nickels
7 dimes
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14 nickels
8 dimes
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12 nickels
9 dimes
That looks like the answer- 3 more nickels than dimes
check:
OK
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