SOLUTION: Word Problem: Find the lesser of two consecutive integers whose sum is greater than 16.

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Question 209139: Word Problem:
Find the lesser of two consecutive integers whose sum is greater than 16.
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the lesser of two consecutive integers whose sum is greater than 16.
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x + x+1>16
2x + 1>16
2x > 15
x>7.5, but since it's an integer
x>8
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It can be any 2 integers greater than 8, 8 & 9, 22 & 23, 12345 & 12346.
It didn't ask for the least, it asked for "the lesser."

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the lesser of two consecutive integers whose sum is greater than 16.

Let the lesser integer be I

Then the larger integer is: I + 1

Since the sum of both is greater than 16, then:

I + I + 1 > 16

2I > 15

I+%3E+15%2F2 = 7.5

Any number greater than 7.5 can be used as the lesser of the two numbers, as long as 1 is added to the lesser chosen number to get the larger number.