SOLUTION: I need help simplifying this problem: { √2x+3) - x+1/(√2x+3) } / 2x+3 I started out like this: A = 2x+3 B = x+1 { √A) - [B/√A)] } /

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: I need help simplifying this problem: { √2x+3) - x+1/(√2x+3) } / 2x+3 I started out like this: A = 2x+3 B = x+1 { √A) - [B/√A)] } /       Log On


   



Question 209063: I need help simplifying this problem:
{ √2x+3) - x+1/(√2x+3) } / 2x+3
I started out like this:
A = 2x+3
B = x+1

{ √A) - [B/√A)] } / A
I'm not sure what to do from here, i'm just supposed to simplify it

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need help simplifying this problem:
{ √(2x+3) - (x+1)/(√(2x+3)) } / (2x+3)
---
In the bracket, establish a common denominator of sqrt(2x+3)
---
{ [[sqrt(2x+3)]^2 - (x+1)]/(√2x+3) } / (2x+3)
---
Simplify within the bracket:
{ [[sqrt(2x+3)]^2 - (x+1)]/(√(2x+3) } / (2x+3)
---
[2x+3-(x+1)]/(2x+3)^(3/2)
---
= [x+2]/(2x+3)^(3/2)
===========================
Cheers,
Stan
Reply to stanbon@comcast.net