SOLUTION: Prove: If an isosceles triangle has an altitude from the vertex to the base, then the altitude bisects the vertex angle.
Given: Triangle ABC is isosceles; Line segment CD is the
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Given: Triangle ABC is isosceles; Line segment CD is the
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Question 209023This question is from textbook Geoemetry
: Prove: If an isosceles triangle has an altitude from the vertex to the base, then the altitude bisects the vertex angle.
Given: Triangle ABC is isosceles; Line segment CD is the altitude to the base AB
Could you help me solve this 2-column proof by using statements and reasons please?
This question is from textbook Geoemetry
Given: Triangle ABC is isosceles;
Line segment CD is the altitude to the base AB
To prove: Angle ACD = angle BCD
angle A = angle B Base angles of isosceles triangle
angle ADC = 90° An altitude of a triangle is
perpendicular to a side
angle BDC = 90° An altitude of a triangle is
perpendicular to a side
angle ADC = angle BDC Both are right angles
Angle ACD = angle BCD If two angles of one triangle are
equal to two angles of another
triangle, the third angles are
equal.
Edwin