SOLUTION: There are four 3-digit natural numbers, each of them equals the sum of the
cube of its digits, three of them are:
153=1+125+27
370=27+343+0
407=64+0+343
What is the 4th one?
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-> SOLUTION: There are four 3-digit natural numbers, each of them equals the sum of the
cube of its digits, three of them are:
153=1+125+27
370=27+343+0
407=64+0+343
What is the 4th one?
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Question 209014: There are four 3-digit natural numbers, each of them equals the sum of the
cube of its digits, three of them are:
153=1+125+27
370=27+343+0
407=64+0+343
What is the 4th one? Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website! There are four 3-digit natural numbers, each of them equals the sum of the
cube of its digits, three of them are:
153=1+125+27
370=27+343+0
407=64+0+343
What is the 4th one?
Since the second one has a 0 on the end,
and since 1 is 13, just add 1
to both sides of it and get
371=27+343+1
Edwin
