SOLUTION: Find the equation of the line that passes through the point (6;-2) and has a slope of –3/2.
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Question 20894
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Find the equation of the line that passes through the point (6;-2) and has a slope of –3/2.
Answer by
algebrapro18(249)
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well here you can either use point slope form or solve the equation y=mx+b for b and then plug in
solving y=mx+b for b and pluging in you get
y=mx+b where m=-3/2 x=6 y=-2
-2=-3/2(6)+b
-2=-9+b
7=b
y=-3/2x+7
using point slope you get
y-y1=m(x-x1) where y1=-2 m=-3/2 x1=6
y-(-2)=-3/2(x-6)
y+2=-3/2x+9
y=-3/2x+9-2
y=-3/2x+7