SOLUTION: twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the intergers.

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Question 208670: twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the intergers.
Found 2 solutions by nerdybill, MathTherapy:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the intergers.
.
Let x = 1st consecutive odd integer
then
x+2 = greater consecutive odd integer
.
2(x+2) = 3x-13
2x+4 = 3x-13
4 = x-13
17 = x
.
Greater integer:
x+2 = 17+2 = 19
.
Therefore, the two integers are 17 and 19

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!
twice the greater of two consecutive odd integers is 13 less than three times the lesser. find the intergers.

Let the smaller of the 2 numbers be S

Then the greater number would be S + 2

Since twice the greater of the 2 odd integers is 13 less than three times the lesser, we will have:

2(S + 2) = 3S - 13

2S + 4 = 3S - 13

2S - 3S = - 13 - 4

- S = - 17

S+=+%28-17%29%2F-1=17

Therefore, the smaller odd integer is highlight_green%2817%29 and the larger consecutive odd integer is highlight_green%2819%29 (17 + 2)
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Check
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Twice the greater integer, 19, is 38 (2 * 19)

3 times the lesser integer is 51 (3 * 17)

Twice the greater integer, or 38 is 13 less than 3 times the lesser integer, or 51 (51 - 13 = 38)