SOLUTION: Hi, I was hoping to get some help with this problem...... The gravitational attraction between two masses varies inversely as the square of the distance between them. The force

Algebra ->  Equations -> SOLUTION: Hi, I was hoping to get some help with this problem...... The gravitational attraction between two masses varies inversely as the square of the distance between them. The force       Log On


   



Question 208577: Hi, I was hoping to get some help with this problem......
The gravitational attraction between two masses varies inversely as the square of the distance between them. The force of attraction is 4 lbs when the masses are 3ft apart, What is the attraction when the masses are 6ft apart?
Thank you so much!!!

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
variation equations can be found here:
http://www.purplemath.com/modules/variatn.htm
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stick with the basic definitions of directly proportional or inversely proportional and this website should help. i'll explain the difference below.
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if y is directly proportional to x, then y = k*x where k is a constant of proportionality.
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if y is inversely proportional to x, then y = k/x where k is a constant of proportionality.
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let's see how these work in practice.
if you want to know how it applies to your problem and skip the tutorial, then just jump to the bottom, otherwise continue.
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y is directly proportional to x with a constant factor of 1
y = x
x = 1,2,3 means y = 1,2,3
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y is directly proportional to x with a constant factor of 10
y = 10x
x = 1,2,3 means y = 10,20,30
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y is directly proportional to x with a constant factor of .5
y = .5x
x = 1,2,3 means y = .5,1,1.5
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y is directly proportional to x with a constant factor of -10
y = -10x
x = 1,2,3 means y = -10,-20,-30
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in all of the above, an increase in the value of x resulted in an increase in the value of y if you disregard the direction of the increase (just look at absolute values).
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now let's look at the same examples using inverse proportion.
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y is inversely proportional to x with a constant factor of 1
y = 1/x
x = 1,2,3 means y = (1),(1/2),(1/3)
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y is inversely proportional to x with a constant factor of 10
y = 10/x
x = 1,2,3 means y = (10/1),(/10/2),(10/3)
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y is inversely proportional to x with a constant factor of .5
y = .5/x
x = 1,2,3 means y = (.5/1),(.5/2),(.5/3)
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y is inversely proportional to x with a constant factor of -10
y = -10/x
x = 1,2,3 means y = (-10/1),(-10/2),(-10/3)
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in all of the above, an increase in the value of x resulted in a decrease in the value of y if you disregard the direction of the increase (just look at absolute values).
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with direct proportion, the absolute value of y increases as the absolute value of x increases, and decreases as the absolute value of x decreases.
if abs(x) goes up, abs(y) goes up, if abs(x) goes down, abs(y) goes down.
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with inverse proportion, the absolute value of y decreases as the absolute value of x increases, and increases as the absolute value of x decreases.
if abs(x) goes up, abs(y) goes down, if abs(x) goes down, abs(y) goes up.
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NOW TO YOUR PROBLEM
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The gravitational attraction between two masses varies inversely as the square of the distance between them.
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The force of attraction is 4 lbs when the masses are 3ft apart.
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What is the attraction when the masses are 6ft apart?
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let d = distance between them.
let g = the gravitational attraction between them.
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since this is an inverse relationship, the general form of our equation should be:
g = k/d^2
where g is the gravitational attraction between them and d is the distance between them and k is the constant of proportionality.
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the problem states that the force of attraction is 4 pounds when the masses are 3 feet apart.
putting this in our equation, we get:
4 = k/3^2
to solve for k, we multiply both sides of this equation by 3^2 to get:
4 * 3^2 = k
this means that k = 4 * 9 = 36
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we now know what k is and we can solve further.
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the question is what is the attraction when the masses are 6 feet apart.
k = 36
d = 6
formula is:
g = 36/d^2
this becomes:
g = 36/36
this becomes:
g = 1
this says that the gravitational attraction between them is 1 pound.
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at 3 feet it's 4 pounds and at 6 feet it's 1 pound. as they get further apart the gravitational attraction gets weaker.
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let's go back to the original equation to see if we got it right.
what is the gravitational pull at 3 feet?
k = 36
d = 3
g = 36/9 = 4
this means the value of k is confirmed as good.
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a word about units.
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g is in pounds and d is in feet.
k = g*d^2 means that k is in square feet pounds.
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our equation of 4 = 36 / 9 is really:
4 pounds = 36 square feet pounds / 9 square feet
when you divide 36 square feet pounds by 9 square feet, the square feet part of the equation cancels out and you are left with 4 pounds.
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you don't normally track the types of units as you go along, but sometime it helps to understand what is going on.
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