SOLUTION: Find the measure of an angle whose supplement measures 38 degree's less than three times it's compliment.
I tried setting it up like this:
180-x=38-3(90-x)
It doesn't seem l
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Angles
-> SOLUTION: Find the measure of an angle whose supplement measures 38 degree's less than three times it's compliment.
I tried setting it up like this:
180-x=38-3(90-x)
It doesn't seem l
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Question 208492: Find the measure of an angle whose supplement measures 38 degree's less than three times it's compliment.
I tried setting it up like this:
180-x=38-3(90-x)
It doesn't seem like the answer i'm getting is the right one, especially when i try checking my answer, can you help please? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the measure of an angle whose supplement measures 38 degree's [sic] less than three times it's [sic] compliment [sic].
I tried setting it up like this:
180-x=38-3(90-x)
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180-x = 3(90-x) - 38 You had the order reversed.
180-x = 270-3x - 38
2x = 52
x = 26 degrees (no apostrophe)
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Check:
Supplement = 154
Complement = 64 (not compliment)
S = 3C - 38?
154 = 3*64 - 38 so it's correct. (It's = it is)
