SOLUTION: find the x-intercepts of the polynomial fuction.state weather the graph crosses the x-axis or touches the x-axis and turns around at each intercept. x^5-30x^3+125x=0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: find the x-intercepts of the polynomial fuction.state weather the graph crosses the x-axis or touches the x-axis and turns around at each intercept. x^5-30x^3+125x=0      Log On


   



Question 208454: find the x-intercepts of the polynomial fuction.state weather the graph crosses the x-axis or touches the x-axis and turns around at each intercept.
x^5-30x^3+125x=0

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
x^5 - 30x^3 + 125x = 0
Factor out x
x(x^4 - 30x^2 + 125) = 0
Factor the quadratic
x(x^2 - 5)(x^2 - 25) = 0
three solutions
x = 0
and
x = +/-sqrt%285%29
and
x = +/-sqrt%2825%29
x = +/-5
:
Each intercept crosses the x axis, as seen on the graph
+graph%28+300%2C+200%2C+-8%2C+8%2C+-100%2C+100%2C+x%5E5-30x%5E3%2B125x%29+