SOLUTION: Find four consecutive integers such that twice the first is subtracted from the sum of the other three is 16.

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Question 208372: Find four consecutive integers such that twice the first is subtracted from the sum of the other three is 16.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Find four consecutive integers such that twice the first is subtracted from the
sum of the other three is 16.
:
Four consecutive integers: x, (x+1), (x+2), (x+3)
:
Write an equation for the statement:
"twice the first is subtracted from the sum of the other three is 16."
-2x + (x+1)+(x+2)+(x+3) = 16
3x - 2x + 6 = 16
x = 16 - 6
x = 10
:
10, 11, 12, 13
:
:
Check solution
-2(10) + 11 + 12 + 13 =
-20 + 36 = 16